Thursday, October 5, 2017

October 05, 2017


How to Calculate Brick, Sand, and Cement Quantity for the Brick Work.

let's take the following brick size:


Length: 190 mm = 0.19M
Width  :   90mm  = 0.09M
Height :   90mm  = 0.09M

Now start the calculation!!!

Consider thickness of mortar: 10 mm = 0.01m
                             &
Mortar Ratio - 1:6 (1-cement and 6 Sand)

Volume of single Brick with Mortar:

= (Length of brick + Thickness of mortar) X
  (Width of brick + Thickness of mortar) X
  (Height of brick + Thickness of mortar)
= (0.190+0.01) X (0.09+0.01) X (0.09+0.01)
= 0.002 CUM

Number of brick in 1 CUM with mortar:
= 1/(volume of brick with mortar)
= 1/0.002
= 500 No’s


Volume of Brick without Mortar:
=Length of brick X Width of brick X height of a brick
=0.190*0.09*0.09
=0.001539 CUM

Volume of bricks without mortar for 1 CUM:
= (No of brick in 1 CUM) X (volume of single brick without mortar)
= 500 X 0.001539
= 0.7695 CUM

Required amount of cement mortar:
= 1 - The volume of bricks without mortar
= 1 - 0.7695
= 0.2305 CUM (Wet condition)

Dry mortar quantity???


The above volume is in wet condition but we need dry condition cement volume.
So multiply 33% as bulkage of sand with wet mortar Quantity.

Dry mortar quantity:
= 0.2305 X 1.33
=0.306565 CUM

Required amount of cement:
= Dry mortar quantity X (1/7) X Density of cement
=0.306565 X (1/7) X 1440 Kg
= 63 Kg =1.26 Kg.

Here 1/7 is taken from the mortar ratio.
1 cement ratio
6 sand ratio

Required amount of sand:
=Dry mortar quantity X (6/7)
= 0.306565 X (6/7)
= 0.26277 CUM

So Finally 1 CUM of brickwork, we need
Bricks = 500 NO’s
Cement = 63 Kg
Sand = 0.263 CUM


Please comment!!!!





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